Given a list of reviews, a list of keywords and an integer k. Find the most popular k keywords in order of most to least frequently mentioned.
The comparison of strings is case-insensitive. Multiple occurances of a keyword in a review should be considred as a single mention. If keywords are mentioned an equal number of times in reviews, sort alphabetically.
Example 1:
Input:
k = 2
keywords = ["anacell", "cetracular", "betacellular"]
reviews = [
"Anacell provides the best services in the city",
"betacellular has awesome services",
"Best services provided by anacell, everyone should use anacell",
]
Output:
["anacell", "betacellular"]
Explanation:
"anacell" is occuring in 2 different reviews and "betacellular" is only occuring in 1 review.
Example 2:
Input:
k = 2
keywords = ["anacell", "betacellular", "cetracular", "deltacellular", "eurocell"]
reviews = [
"I love anacell Best services; Best services provided by anacell",
"betacellular has great services",
"deltacellular provides much better services than betacellular",
"cetracular is worse than anacell",
"Betacellular is better than deltacellular.",
]
Output:
["betacellular", "anacell"]
Explanation:
"betacellular" is occuring in 3 different reviews. "anacell" and "deltacellular" are occuring in 2 reviews, but "anacell" is lexicographically smaller.
-
from collections import defaultdict def top_k(keywords, reviews, k_val): counts = defaultdict(int) for review in reviews: words_set = set() words = review.split() for word in words: lower_case_word = word.strip(',.').lower() words_set.add(lower_case_word) for keyword in keywords: if keyword in words_set: counts[keyword] += 1 return sorted(counts.keys(), key=lambda k: (-counts[k], k))[0:k_val] -
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